In C++Standard librarymiddle,std::decay_t
It's a very usefulType conversionTools that can help us deal with decay. This article will introduce in detailstd::decay_t
use, working principle and some practical application scenarios.
What is Type Decay?
In C++, type degradation means that in some cases, the type of a variable will change. Common types of degradation include:
- Array to pointer degradation: When an array is passed as a function parameter, it degenerates into a pointer to its first element.
- Degradation of function-to-function pointer: When a function is passed as a function parameter, it degenerates into a pointer to that function.
-
Remove references and CV qualifiers: Remove references of types (
&
or&&
) and CV qualifiers (const
andvolatile
)。
std::decay_t
Definition
std::decay_t
yesC++14 One introducedType aliasTemplate, defined in<type_traits>
in the header file. Its definition is as follows:
template< class T >
using decay_t = typename decay<T>::type;
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std::decay
is a type trait that implements type degradation through template specialization and type conversion. Specifically,std::decay
The following steps will be performed in turn:
- if
T
It is an array type, and it degenerates into a pointer to the array element type. - if
T
It is a function type, and it degenerates into a pointer to the function. - Remove
T
quotation and CV qualifiers.
Sample code
The following is a sample code to showstd::decay_t
Practical Application:
Example 1: Array to pointer degradation
#include <iostream>
#include <type_traits>
int main() {
using ArrayType = int[5];
using DecayedType = std::decay_t<ArrayType>;
std::cout << std::is_same<DecayedType, int*>::value << std::endl; // Output: 1 (true)
return 0;
}
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In this example,ArrayType
It is one containing 5int
array type. passstd::decay_t
, we degenerate it intoint*
type.
Example 2: Degradation of function-to-function pointer
#include <iostream>
#include <type_traits>
void foo() {}
int main() {
using FunctionType = void();
using DecayedType = std::decay_t<FunctionType>;
std::cout << std::is_same<DecayedType, void(*)()>::value << std::endl; // Output: 1 (true)
return 0;
}
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In this example,FunctionType
is a function typevoid()
. passstd::decay_t
, we degenerate it intovoid(*)()
Type, i.e. pointer to the function.
Example 3: Remove references andCVQualifier
#include <iostream>
#include <type_traits>
int main() {
using ReferenceType = const int&;
using DecayedType = std::decay_t<ReferenceType>;
std::cout << std::is_same<DecayedType, int>::value << std::endl; // Output: 1 (true)
return 0;
}
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In this example,ReferenceType
It's oneconst int&
type. passstd::decay_t
, we degenerate it intoint
type, remove references andconst
Qualifier.
Practical application scenarios
std::decay_t
Metaprogramming in templates andGeneric ProgrammingVery useful in. For example, when implementing generic functions or class templates, we often need to deal with different types of parameters and make sure they have consistent type representations in some cases.std::decay_t
Can help us achieve this.
Example: Generic Function Template
#include <iostream>
#include <type_traits>
template<typename T>
void print_type() {
using DecayedType = std::decay_t<T>;
std::cout << typeid(DecayedType).name() << std::endl;
}
int main() {
print_type<int[5]>(); // Output: int*
print_type<void()>(); // Output: void(*)()
print_type<const int&>(); // Output: int
return 0;
}
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In this example, we define a generic function templateprint_type
, it usesstd::decay_t
To print the degraded type.
Summarize
std::decay_t
is a powerful tool for handling the situation of type degradation. By understanding its working principles and application scenarios, we can handle type conversion issues more flexibly in template metaprogramming and generic programming. Hope this article helps you better understand and use itstd::decay_t
。
If you have any questions or need further explanation, feel free to ask!